Answer :
[tex]\frac{5}{6}x-2x+\frac{4}{3}=\frac{5}{3}\ \ \ \ \ \ \ |multiply\ both\ sides\ by\ 6\\\\6\times\frac{5}{6}x-6\times2x+6\times\frac{4}{3}=6\times\frac{5}{3}\\\\5x-12x+8=10\\\\-7x=10-8\\\\-7x=2\ \ \ \ \ \ |divide\ both\ sides\ by\ (-7)\\\\\boxed{x=-\frac{2}{7}}[/tex]