Answer :

[tex]\left\{\begin{array}{ccc}y=3x+5\\y=-5x-3\end{array}\right\\\\substitution\ method\\\\3x+5=-5x-3\\3x+5x=-3-5\\8x=-8\ \ \ \ \ /:8\\x=-1\\\\y=3(-1)+5=-3+5=2\\\\Solution:x=-1\ and\ y=2.[/tex]

[tex]graphing\ method\\\\ \left\{\begin{array}{ccc}y=3x+5\\y=-5x-3\end{array}\right\\------------------\\y=3x+5\\y-intercept\ (x=0)\\y=3(0)+5=5\\(0;\ 5)\\x-intercept\ (y=0)\\3x+5=0\\3x=-5\\x=-\frac{5}{3}\\(-\frac{5}{3};\ 0)\\---------------------[/tex]
[tex]y=-5x-3\\y-intercept\ (x=0)\\y=-5(0)-3=-3\\(0;-3)\\x-intercept\ (y=0)\\-5x-3=0\\-5x=3\\x=-\frac{3}{5}\\(-\frac{3}{5};\ 0)\\\\Solution:((-1;\ 2)\to x=-1\ and\ y=2.[/tex]
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