Answered

A particular circle in the standard (x,y) coordinate
plane has an equation of (x − 5)^2 + y^2 = 38. What are
the radius of the circle, in coordinate units, and the
coordinates of the center of the circle?
radius center
F. 38 ( 5,0)
G. 19 ( 5,0)
H. 38 ( 5,0)
J. 38 (−5,0)
K. 19 (−5,0)

Answer :

[tex]the\ center\ of\ the\ circle:(a;\ b)\\the\ radius:r\\\\then\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\=========================\\\\(x-5)^2+y^2=38\\\\(x-5)^2+(y-0)^2=(\sqrt{38})^2\\\\center:(5;\ 0)\\radius:\sqrt{38}[/tex]

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