Answer :
Step-by-step explanation:
the last division step must have given us
ax + b
- ax + 2a
-----------------------
0 + b-2a = -132
b = 2a - 132
as we can see, we have 2 variables with only one equation. so, there are infinitely many functions that have a remainder of -132 when divided by (x + 2).
but as special case we can assume b = 0, and then
0 = 2a - 132
132 = 2a
a = 66
so, the function could look like
f(x) = ... + 66x
and then a division by (x + 2) would have a result of 66 and a remainder of -132.
but as I said this is only one of infinitely many possibilities.
e.g.
f(x) = ... + 64x - 4
the division by (x + 2) would have a result of 64 and a remainder of -132 (2a = 2×64 = 128, b = -4).