Acceleration is sometimes expressed in multiples of g, where g=9.8 m/s squared is the acceleration due to the earth's gravity. In a car crash, the car's velocity may go from 30 m/s to 0 m/s in 0.15s How many g's are experienced, on average, by the driver?

Answer :

Answer:

20.4

Explanation:

Average acceleration is the change in velocity over time.

a = (v − u) / t

where a is acceleration,

v is final velocity,

u is initial velocity,

and t is time.

Given v = 0 m/s, u = 30 m/s, and t = 0.15 s:

a = (0 − 30) / 0.15

a = -200 m/s²

As a multiple of g, the magnitude of the acceleration is:

|a| = 200 m/s² × (1 g / 9.8 m/s²) = 20.4g

The driver experiences 20.4 g's.