A hockey season ticket holder pays $77.52 for her tickets plus $6.00 for a program each game. A second person pays $18.92 for a ticket to every game, but doesn't buy programs. In how many games will they have paid the same amount?

Answer :

Answer: To find out how many games the two people will have paid the same amount, we can set up an equation to represent the total cost for each person.

the number of games played is shown as \(x\).

For the hockey season ticket holder:

Total cost = Cost of tickets + (Cost of program per game * Number of games)

Total cost = $77.52 + ($6.00 (x))

For the second person:

Total cost = Cost of ticket per game × Number of games

Total cost = $18.92 (x)

To find the number of games where they will have paid the same amount, we can set up an equation where the total costs are equal for both people:

$77.52 + ($6.00x) = $18.92x

Now, we solve for (x):

$77.52 + $6.0x = $18.92x

$77.52 = $18.92x - $6.00x

$77.52 = $12.92x

(x) = $77.52 / $12.92

(x) ≈ 6 games

Therefore, the two people will have paid the same amount after 6 games.

Step-by-step explanation: