The length and width of the rectangle are 23 m and 11 m.
Given,
A rectangle is 12m longer than it is wide.
Its perimeter is 68.
We need to find its length and width.
A rectangle is a quadrilateral with four sides and four angles where the opposite sides are equal and parallel and the angles are right-angled.
Area of a rectangle = Length x Width.
Perimeter of a rectangle = 2 ( Length + Width ).
We have,
A rectangle is 12m longer than it is wide.
Let length = L and wide = W.
We can write it as,
L = 12 + W.
We have,
Its perimeter is 68.
Let P be the perimeter of the rectangle.
P = 2 ( L + W )
68 = 2 ( L + W )
68 / 2 = L + W
34 = L + W
Putting L = 12 + W
We get,
34 = 12 + W + W
34 = 12 + 2W
34 - 12 = 2W
22 = 2W
W = 11 m.
Putting W = 11 in L = 12 + W.
We get,
L = 12 + 11
L = 23 m.
Thus, the Length and Width of the rectangle are 23 m and 11 m.
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